(x+4)^2=(x+12)(x)

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Solution for (x+4)^2=(x+12)(x) equation: 



(x+4)^2=(x+12)(x)

We move all terms to the left:

(x+4)^2-((x+12)(x))=0



We calculate terms in parentheses: -((x+12)x), so:

(x+12)x

We multiply parentheses

x^2+12x

Back to the equation:

-(x^2+12x)



We get rid of parentheses

-x^2+(x+4)^2-12x=0

We add all the numbers together, and all the variables

-1x^2-12x+(x+4)^2=0

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